(3x^(2/3))+(10x^(1/3))=8

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Solution for (3x^(2/3))+(10x^(1/3))=8 equation: 


x in (-oo:+oo)

3*x^(2/3)+10*x^(1/3) = 8 // - 8

3*x^(2/3)+10*x^(1/3)-8 = 0

t_1 = x^(1/3)

3*t_1^2+10*t_1^1-8 = 0

3*t_1^2+10*t_1-8 = 0

DELTA = 10^2-(-8*3*4)

DELTA = 196

DELTA > 0

t_1 = (196^(1/2)-10)/(2*3) or t_1 = (-196^(1/2)-10)/(2*3)

t_1 = 2/3 or t_1 = -4

t_1 = -4

x^(1/3)+4 = 0

1*x^(1/3) = -4 // : 1

x^(1/3) = -4

( -4 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 2/3

x^(1/3)-2/3 = 0

1*x^(1/3) = 2/3 // : 1

x^(1/3) = 2/3

x^(1/3) = 2/3 // ^ 3

x = 8/27

x = 8/27

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